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b)(0,3^3)^9=0,3^27
(0,3^2)^15=0,3^30
0,3^30>0,3^27
c) (0,36)^4*0,36 > (0,216)^4
d)(2*(1/16))^10 > 1/16^12
e)(5^3)^150=5^450
(5^2)^225=5^450
5^450=5^450
f)[(10^2)/(3^2)]^12=((3 1/3)^2)^12=(3 1/3^24)
[(10^3)/(3^3)]^9=((3 1/3)^3)^9=(3 1/3^27)
(3 1/3^24)<(3 1/3^27)