Zadanie w załączniku.
Podstawa: trójkąt równoboczny: Pp=a*pierw(3)/4=5pierw(3)/4
Ppb=3*(5*10)=150
Pc=2*(5pierw(3)/4)+150=5pierw(3)/2+150=(5pierw(3)+300)/2
V=(5pierw(3)/4)*10=(25pierw(3))/2
Pp = 5 do 2 x pierw z 3 / 4 = 25 pierw 3 / 4 = 6,25 pier z 3
Pb = n x a x h = 3 x 5 x 10 = 150
Pc = 2 x 6,25 pierw z 3 + 150 = 12,5 pier .z 3 + 150 V = PP x h = 6,25 pier z 3 x 10 = 62,5 pier z 3
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Podstawa: trójkąt równoboczny: Pp=a*pierw(3)/4=5pierw(3)/4
Ppb=3*(5*10)=150
Pc=2*(5pierw(3)/4)+150=5pierw(3)/2+150=(5pierw(3)+300)/2
V=(5pierw(3)/4)*10=(25pierw(3))/2
Pp = 5 do 2 x pierw z 3 / 4 = 25 pierw 3 / 4 = 6,25 pier z 3
Pb = n x a x h = 3 x 5 x 10 = 150
Pc = 2 x 6,25 pierw z 3 + 150 = 12,5 pier .z 3 + 150
V = PP x h = 6,25 pier z 3 x 10 = 62,5 pier z 3