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180° - (δ + 90°) + 180° - (γ + 90°) = ∡BAC = 50°
180° - δ - 90° + 180° - γ - 90° = 50°
180° - 50° = δ + γ
δ + γ = 130°
180° - (α + 90°) + 180° - (β + 90°) = ∡ABC = 70°
180° - α - 90° + 180° - β - 90° = 70°
180° - 70° = α + β
α + β = 110°
γ = 180° - (α + β) = 180° - 110° = 70°
180° - (α + 90°) + 180° - (γ + 90°) = ∡BCA = 60°
180° - α - 90° + 180° - γ - 90° = 60°
180° - 60° = α + γ
α + γ = 120°
δ + γ = 130°
δ + 70° = 130°
δ = 130° - 70° = 60°
α + γ = 120°
α + 70° = 120°
α = 120° - 70° = 50°
α + β = 110°
50° + β = 110°
β = 110° - 50° = 60°
odp
α = 50° , β = 60° , γ = 70° , δ = 60°
sprawdzenie
2α + β + δ + 2γ = 360°
2 * 50° + 60° + 60° + 2 * 70° = 360°
100° + 60° + 60° + 140° = 360°
360° = 360°
L = P