zadanie w załączniku
(2²)⁻³= 2⁻⁶=(½)⁶=1/64
(2⁻³)⁻²=2⁶=64
[(-½)²]⁻³=(-½)⁻⁶=(-2)⁶=64
[(-2)⁻³]⁻²=(-2)⁶=64
[(-2)²]⁻³=(-2)⁻⁶=(-½)⁶=1/64
[(½)⁻²]⁻⁴=(½)⁸=1/256
[(-0,1)⁻²]⁻⁴=(-0,1)⁸=0,00000001
[(-2x)⁻⁴]³=(-2x)⁻¹²=(-½x)¹²
Proszę :)
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(2²)⁻³= 2⁻⁶=(½)⁶=1/64
(2⁻³)⁻²=2⁶=64
[(-½)²]⁻³=(-½)⁻⁶=(-2)⁶=64
[(-2)⁻³]⁻²=(-2)⁶=64
[(-2)²]⁻³=(-2)⁻⁶=(-½)⁶=1/64
[(½)⁻²]⁻⁴=(½)⁸=1/256
[(-0,1)⁻²]⁻⁴=(-0,1)⁸=0,00000001
[(-2x)⁻⁴]³=(-2x)⁻¹²=(-½x)¹²
Proszę :)