Question

Zadanie w załączniku

Answer 1

Odpowiedź:

zad 1

a = (3 - 3⁻¹)² = (3 - 1/3)² = (2 3/3 - 1/3)² = (2 2/3)² = (8/3)² = 64/9 = 7 1/9

b = (2 2/3)² = (8/3)² = 64/9 = 7 1/9

a = b

Odp: A

zad 2

a)

(2 1/3)³ * (1/7)³ = (2 1/3 * 1/7)³ = (7/3 * 1/7)³ = (1/3)³ = 1/27

b)

(1/2)⁴/(0,125)³ = (1/2)⁴/(1/8)³ = (1/2)⁴/[(1/2)³]³ = (1/2)⁴/(1/2)⁹ = (1/2)⁴⁻⁹ =

= (1/2)⁻⁵ = 2⁵ = 32

zad 3

[(ab⁻²)³ : a⁻¹]/a²b⁻⁴ = (ab⁻⁶ : a⁻¹)/a²b⁻⁴ = (a : a⁻¹ * b⁻⁶)/a²b⁻⁴ =

=(a¹⁻¹ * b⁻⁶)/a²b⁻⁴ = b⁻⁶/a²b⁻⁴ = b⁻⁶⁺⁴/a² = b⁻²/a² = 1/a²b²

Answer 2

Odpowiedź:

Zadanie wykonam w załączniku

Szczegółowe wyjaśnienie: