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25-x²≥0
(5-x)(5+x)=0
x=5 ∨ x=-5
x∈< -5,5>
2]
(x-3)²<(x-2)(2x-10)
x²-6x+9< 2x²-10x-4x+20
x²-2x²-6x+14x+9-20<0
-x²+8x-11<0
Δ=b²-4ac=64-44=20 √Δ=2√5
x1=[-b-√Δ]/2a=[-8-2√5]/-2=4+√5
x2=[-b+√Δ]/2a=[-8+2√5]/-2=4-√5
x∈(-∞;4-√5) ∨(4+√5;+∞)