zadanie w załączniku zadanie 3 dam naj na 100%
a)(-12)+ (-8) - (+7)-(-9)= -12 -8 -7 +9 = -18
8 - (-9) + (-11) - (+5) = 8+9 -11 - 5 =1
-21 +(- 7 )- (+15)- (-32)= -21 -7 - 15 +32=-11
-(-13) + (-2) - (+16) + (-5)= 13 -2 -16 -5= -10
b)[(-16) - (-4)]- (-8+6) = -16+4+8 -6=-10
[-(+11) -(-6) ] + (-5 +8)= -11 +6 -5 +8 =-2
(-19)-[-(-18)-(+7)] + (-34)=-19 - 18 +7 -34 = -64
-(+27) - (-26 - 17) + (+14)= 57-27=30
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a)(-12)+ (-8) - (+7)-(-9)= -12 -8 -7 +9 = -18
8 - (-9) + (-11) - (+5) = 8+9 -11 - 5 =1
-21 +(- 7 )- (+15)- (-32)= -21 -7 - 15 +32=-11
-(-13) + (-2) - (+16) + (-5)= 13 -2 -16 -5= -10
b)[(-16) - (-4)]- (-8+6) = -16+4+8 -6=-10
[-(+11) -(-6) ] + (-5 +8)= -11 +6 -5 +8 =-2
(-19)-[-(-18)-(+7)] + (-34)=-19 - 18 +7 -34 = -64
-(+27) - (-26 - 17) + (+14)= 57-27=30