Odpowiedź:
zad 8:
a) 8 [cm]
b) 5 [m]
c) 7 [km]
zad 9:
P = 15*18/2
P = 135
135/32 = 4,21875
to 5 wywrotek musieli przywieźć
zad 10:
P = 1/2*a*b
24 = 1/2*6*b /3
b = 8
zad 11:
2,05 [m] = 205 [cm] <== dłuższa przyprostokątna
205 - 26 = 179 [cm] <== krótsza przyprostokątna
P = 1/2*205*179
P = 18.347,5 [cm^2]
P = 1,83475 [m^2]
zad 13:
a) P = 10*12 - 1/2*7*7
P = 120 - 24,5
P = 95,5
b) P = 12*8 - 1/2*3*4 - 1/2*4*4 - 1/2*4*7 -1/2*3*4
P = 96 - 6 - 8 - 14 - 6
P = 62
zad 14:
a <= szerokość obrazka
a+ 2 = 20
a = 18
a- 3 = 18 - 3 = 15 <== wysokość obrazka
P_ob = 18*15
P_ob = 270 [cm^2]
P_ram = 20*20 - P_ob
P_ram = 400 - 270
P_ram = 130 [cm^2]
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Odpowiedź:
zad 8:
a) 8 [cm]
b) 5 [m]
c) 7 [km]
zad 9:
P = 15*18/2
P = 135
135/32 = 4,21875
to 5 wywrotek musieli przywieźć
zad 10:
P = 1/2*a*b
24 = 1/2*6*b /3
b = 8
zad 11:
2,05 [m] = 205 [cm] <== dłuższa przyprostokątna
205 - 26 = 179 [cm] <== krótsza przyprostokątna
P = 1/2*205*179
P = 18.347,5 [cm^2]
P = 1,83475 [m^2]
zad 13:
a) P = 10*12 - 1/2*7*7
P = 120 - 24,5
P = 95,5
b) P = 12*8 - 1/2*3*4 - 1/2*4*4 - 1/2*4*7 -1/2*3*4
P = 96 - 6 - 8 - 14 - 6
P = 62
zad 14:
a <= szerokość obrazka
a+ 2 = 20
a = 18
a- 3 = 18 - 3 = 15 <== wysokość obrazka
P_ob = 18*15
P_ob = 270 [cm^2]
P_ram = 20*20 - P_ob
P_ram = 400 - 270
P_ram = 130 [cm^2]