Zadanie w załączniku Daję naj!.... Question from @Lenissa

Lenissa @Lenissa

April 2022 2 4 Report

Zadanie w załączniku
Daję naj!

smuffy123

Odpowiedź:

Szczegółowe wyjaśnienie:

a) √144 + ∛64 = 12 + 4 = 16

b) ∛12² + 856 = ∛1000 = 10

c) ∛15³ + √7² = 15 + 7 = 22

d) (√32 + 2√2) / √2 = (√64 + 2·2) / 2 = 12 /2 = 6

e) ∛2 · ∛4 + √12 · √3 = ∛8 + √36 = 2 + 6 = 8

0 votes Thanks 0

Velta

a) $\sqrt{144}+\sqrt[3]{64}=\sqrt{12\cdot12}+\sqrt[3]{4\cdot4\cdot4}=12+4=\boxed{16}$

b) $\sqrt[3]{12^2+856}=\sqrt[3]{144+856}=\sqrt[3]{1\,000}=\sqrt[3]{10\cdot10\cdot10}=\boxed{10}$

c) $\sqrt[\not3]{15^{\not3}}+\sqrt{7^{\not2}}=15+7=\boxed{22}$

d) $\frac{\sqrt{32}+2\sqrt{2}}{\sqrt{2}}=\frac{\sqrt{16\cdot2}+2\sqrt{2}}{\sqrt{2}}=\frac{4\sqrt{2}+2\sqrt{2}}{\sqrt{2}}=\frac{6\sqrt{2}}{\sqrt{2}}=\boxed{6}$

e) $\sqrt[3]{2}\cdot\sqrt[3]{4}+\sqrt{12}\cdot\sqrt{3}=\\=\sqrt[3]{2\cdot4}+\sqrt{12\cdot3}=\\=\sqrt[3]{8}+\sqrt{36}=\\=2+6=\boxed{8}$

2 votes Thanks 1

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