Proszę pomóżcie dam Naj .Czekam do godz . 17:10.
Z góry dzięki.
28,8π=162°/360°·πr²
28,8π=0,45·πr²
r²=28,8π:0.45π
r²=64
r=√64=8cm
r=8cm
360°-162°=198°
l=α/306°·2πr l=198°/360°·2π·8=0,55·16π=8,8πcm
l=162°/360°·2π·8=0,45·16π=7,2π 8,8π+7,2π=16πcm
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
28,8π=162°/360°·πr²
28,8π=0,45·πr²
r²=28,8π:0.45π
r²=64
r=√64=8cm
r=8cm
360°-162°=198°
l=α/306°·2πr l=198°/360°·2π·8=0,55·16π=8,8πcm
l=162°/360°·2π·8=0,45·16π=7,2π 8,8π+7,2π=16πcm