zadanie oblicz pole trapezu wiedząc że A) a=1dm,b=5cm,h=2cm B) a=0,4m,b=70cm,h=2dm C) a=15cm,b=1,5m,h=1,5dm
P= (a+b)*h*1/2
a) P=(1dm+5cm)*2cm*1/2=15cm^2
b) P=(0,4m+70cm)*2dm*1/2=11dm^2
c) P= (15cm+1,5m)*1,5dm*1/2=(1,5dm+15dm)*3/4dm=49,5/4 dm^2=
12 1,5/4 dm^2=12,375 dm^2
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P= (a+b)*h*1/2
a) P=(1dm+5cm)*2cm*1/2=15cm^2
b) P=(0,4m+70cm)*2dm*1/2=11dm^2
c) P= (15cm+1,5m)*1,5dm*1/2=(1,5dm+15dm)*3/4dm=49,5/4 dm^2=
12 1,5/4 dm^2=12,375 dm^2