Question

Zadanie nr 2 daje nj

Answer 1

A)
(x²-9)/(x²-3x) = (x+3)(x-3) / [x(x-3)]
x≠0 i x≠3
D=R \{0, 3}
m.z. x+3=0
x=-3
b)
D=(-∞, 6)
5-x=0
x=5 ∉ D
2x+4=0
2x=-4
x=-2
m.z. x=-2.