Odpowiedź:
Szczegółowe wyjaśnienie:
1) log₂32 = 5 , bo 2⁵ = 32
2) logₓ 5 = 2 --> x² = 5 --> x = √5
3) log₃ x = 3 , x = 3³ = 27
4) log₂ 4 + log₂ 64 = 2 + 6 = 8 lub log₂(4 · 64) = log₂256 = 8
5) log₃ 81 - log₃ 3 = 4 - 1 = 3 lub log₃(81/3) = log₃ 27 = 3
6) log₃ 3⁵ = 5 · log₃ 3 = 5 · 1 = 5
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Odpowiedź:
Szczegółowe wyjaśnienie:
1) log₂32 = 5 , bo 2⁵ = 32
2) logₓ 5 = 2 --> x² = 5 --> x = √5
3) log₃ x = 3 , x = 3³ = 27
4) log₂ 4 + log₂ 64 = 2 + 6 = 8 lub log₂(4 · 64) = log₂256 = 8
5) log₃ 81 - log₃ 3 = 4 - 1 = 3 lub log₃(81/3) = log₃ 27 = 3
6) log₃ 3⁵ = 5 · log₃ 3 = 5 · 1 = 5