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AB = √(3+1)² + (-5-6)²
AB = √4 + 121
AB = √125 = 5√5
P = (5√5)² = 125 [j²]
L = 4 * 5√5 = 20√5
(wektor)AB = [3+1, -5-6]
(wektor)AB = [4,-11]
wektor przeciwny do AB to (wektor)BA
(wektor)BA = [-4,11]
2. (wektor)AB = (wektor)CD
A(-8,4) B(0,-8) C(4,-6) D(x,y)
(wektor)AB = [0+8, -8-4] = [8, -12]
(wektor)CD = [4-x, -6-y]
4 - x = 8 -6 - y = -12
x = -4 y = 6
3.C(x, y) A(10,-5) B(-25,10)
3(wektor)AC = 2(wektor)CB
3[x - 10, y + 5] = 2[-25 - x, 10 - y]
3(x - 10) = 2(-x - 25) 3(y + 5) = 2(10 - y)
3x - 30 = -2x - 50 3y +15 = 20 - 2y
5x = -20 5y = 5
x = -4 y = 1
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