zadania w załączniku, bardzo pilne.... Question from @39271057281

39271057281 @39271057281

November 2018 1 3 Report

zadania w załączniku, bardzo pilne

luki130193

Zad.6

Dane:

x Maciek

x+8,32 Krzyś

x+x+8,32=26,40

2x=26,40-8,32

2x=18,08/:2

x=9,04 - Maciek

x+8,32= 9,04+8,32=17,36 Krzyś

Zad.7

Dane:

a=4,6 m

b=2,7 m

P=a*b=4,6*2,7=12,43 $m^2$

$3,5 m^2$ - 1 puszka farby

$12,42 m^2$ - x puszek farby

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$x=\frac{12,42}{3,5}=\frac{\frac{1242}{100}}{\frac{35}{10}}=\frac{1242}{100}*\frac{10}{35}=\frac{1242}{350}\approx3,55$ puszek

Zad.2

$6-3\frac{1}{3}*1\frac{1}{5}=6-\frac{10}{3}*\frac{6}{5}=6-4=2$

$0,2+3\frac{1}{3}:\frac{3}{4}=0,2+\frac{10}{3}*\frac{4}{3}=0,2+\frac{40}{9}=\frac{2}{10}+\frac{40}{9}=\frac{1}{5}+\frac{40}{9}=\frac{9}{45}+\frac{200}{45}=\frac{209}{45}=4\frac{29}{45}$

$\frac{10,2-1\frac{2}{5}}{6\frac{1}{4}*\frac{2}{3}+\frac{1}{2}}=\frac{10,2-1,4}{\frac{25}{4}*\frac{2}{3}+\frac{1}{2}}=\frac{8,8}{\frac{25}{6}+\frac{1}{2}}=\frac{8,8}{\frac{25}{6}+\frac{3}{6}}=\frac{\frac{88}{10}}{\frac{28}{6}}=\frac{88}{10}*\frac{6}{28}=\frac{66}{35}=1\frac{31}{35}$

Zad.3

$(4\frac{1}{4}-1\frac{1}{8})(4\frac{1}{4}+1\frac{1}{8})=(\frac{17}{4}-\frac{9}{8})(\frac{17}{4}+\frac{9}{8})=(\frac{17}{4})^2-(\frac{9}{8})^2=\frac{289}{16}-\frac{81}{64}=\frac{1156}{64}-\frac{81}{64}=\frac{1075}{64}=16\frac{51}{64}$

$(2\frac{3}{4}-1\frac{2}{5})(2\frac{3}{4}+1\frac{2}{5})=(\frac{11}{4}-\frac{7}{5})(\frac{11}{4}+\frac{7}{5})=(\frac{11}{4})^2-(\frac{7}{5})^2=\frac{121}{16}-\frac{49}{25}=\frac{3025}{400}-\frac{784}{400}=\frac{2241}{400}=5\frac{241}{400}$

Zad.4

$\frac{1\frac{2}{7}+2\frac{1}{3}}{2\frac{2}{5}-1\frac{1}{3}}=\frac{\frac{9}{7}+\frac{7}{3}}{\frac{12}{5}-\frac{4}{3}}=\frac{\frac{27}{21}+\frac{49}{21}}{\frac{36}{15}-\frac{20}{15}}=\frac{\frac{76}{21}}{\frac{16}{15}}=\frac{76}{21}*\frac{15}{16}=\frac{95}{28}=3\frac{11}{28}$

$\frac{7\frac{3}{4}+1\frac{2}{5}}{2*1\frac{1}{2}*\frac{7}{3}}=\frac{\frac{31}{4}+\frac{7}{5}}{2*\frac{3}{2}*\frac{7}{3}}=\frac{\frac{155}{20}+\frac{28}{20}}{7}=\frac{\frac{183}{20}}{7}=\frac{183}{20}*\frac{1}{7}=\frac{183}{140}=1\frac{43}{140}$

$\frac{5}{8}*0,7-\frac{0,3}{1\frac{1}{2}}=\frac{5}{8}*\frac{7}{10}-\frac{\frac{3}{10}}{\frac{3}{2}}=\frac{7}{16}-\frac{3}{10}*\frac{2}{3}=\frac{7}{16}-\frac{1}{5}=\frac{35}{80}-\frac{16}{80}=\frac{19}{80}$