Question

Zadania sa w zalaczniku ;)) prosze o pomoc.

Answer 1

a) (x-3)^2-3(x+2)^2= x^2-3x+9-3(x^2+4x+4)=x^2-3x+9-3x^2-12x-12=-2x^2-15x-3  (teraz delte możesz)

b)2(1-x)^2+(x-2)^2=2(1-2x+x^2)+x^2-4x+4=2-4x+2x^2+x^2-4x+4=3x^2-8x+6

c) -3(4x^2-4x+1)-(x^2-3x+2x-6)=12x^2+12x-3-x^2+3x-2x+6=-13x^2+13x+3

d)5(x^2+10x+25)+3(1-2x+x^2)=5x^2+50+125+3-6x+3x^2=8x^2+44x+128

e)2(x^2+4x-3x-12)-(25x^2-20x+4)=2x^2+8x-6x-24-25x^2+20x-4=-23x^2+22x-28

f)9x^2+24x+16+2(4-4x+x^2)=9x^2+24x+16+8-8x+2x^2=11x^2+16x+24

g)7(x^2+2x+1)-6(x^2-2x+1)=7x^2+14x+7-6x^2+12x-6=x^2+26x+1

h)-2(x-x^2+2+2x)+5(x^2-12x+36)=-2x+2x^2-4-4x+5x^2-60x+180=7x^2-66x+180

i)4(2x^2+5x-6x-15)-3(x^2+6x+9)=8x^2+20x-24x-60-3x^2-18-27=5x^2-22x-87

j)9x^2+30x+25+2(49x^2-14x+1)=9x^2+30x+25+98x^2-28x+2=89x^2+2x+27

k)-8(4x^2+4x+1)-5(16x^2+16x+4)=-32x^2-32x-8-80x^2-80x-20=-112x^2-112x-28

l)-(x^2-6x+9)+7(1-2x+x^2)=-x^2+6x-9+7-14x+7x^2=6x^2-8x-2