Zad.6
Obwód prostokatnej działki wynosi 62m. Pole powierzchni tej działki wynosi ?
a = 2x-1 b = x+2
Obw=62m
Obw=2a+2b
62=2(2x-1) + 2(x+2)
62=4x-2+2x+4
62=6x+2 |-2
62-2=6x
60=6x |:6
x=10m
a=2*10m-1m
a=19m
b=10m+2m
b=12m
P=ab
P=19m*12m
P=228 m^2
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Obw=62m
Obw=2a+2b
62=2(2x-1) + 2(x+2)
62=4x-2+2x+4
62=6x+2 |-2
62-2=6x
60=6x |:6
x=10m
a=2*10m-1m
a=19m
b=10m+2m
b=12m
P=ab
P=19m*12m
P=228 m^2