Zad1
oblicz stosunek masowy
a)N20
b)NO
zad2
Oblicz zawartość procentową tych pierwiastków w tych tlenkach
a) N2O 28 : 16 7 : 4
B) NO 14 : 16 7 : 8
a)mN2O = 2 * 14u+ 16u = 44u
mN2 = 2 * 14u = 28 u
100% ------ 44u x ---------- 28u
x = 63,6 %
b) mNO = 14u + 16u = 30u mN = 16u
100% ---------- 30u
x ------------------ 16u
x = 53 %
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a) N2O
28 : 16
7 : 4
B) NO
14 : 16
7 : 8
a)mN2O = 2 * 14u+ 16u = 44u
mN2 = 2 * 14u = 28 u
100% ------ 44u
x ---------- 28u
x = 63,6 %
b) mNO = 14u + 16u = 30u
mN = 16u
100% ---------- 30u
x ------------------ 16u
x = 53 %