Question

Zad.10 jest w załączniku, proszę o pełne odp. jak nie to spam :) dam naj.

Answer 1

a) (4a³)⁴:(½a²)³= (256a¹²):(⅛a⁶) = 256·8a⁶= 2048a⁶ = 2048 ·(-½)⁶ = 2048 ·1/64 = 32

b) (25x²y²):(5xy)³ = (25x²y²)/(125x³y³) = 1/5xy= 1/[5·(-2)·⅕] = -½

c) (3ab²c³)·(5a²b²c²) = 15a³b⁴c⁵ = 15·(0,1)³·10⁴·(-1)⁵ = 15·0,001·10000·(-1)=

                                = -15·10 = -150

d) (7x⁶y⁵z⁴):(5x⁴y³z²) = 7/5·x²y²z²= 7/5·(-5)²·(1/7)²·(-1)²= 7/5·25·1/49·1 =5/7

e) [(2a²)/(3b²)]⁵·[(3b⁴)/(2a²)]⁴= (32a¹⁰)/(243b¹⁵) · (81b¹⁶)/(16a⁸) = ⅔a²b =

                                             =  ⅔·(½)²·(-⅓)= ⅔ · ¼ · (-⅓) = -1/18