Question

Zad 3 i 4 ;)

Answer 1

3.
a) Dane
a = 2cm
b = 1dm = 10cm
c = 5mm = 0,5 cm

Rozwiązanie
V = abc
V = 2 x 10 x 0,5
V = 20 x 0,5
V = 10cm³

Pc = 2x(ab + bc + ac)
Pc = 2x(2x10 + 10x0,5 + 2x0,5)
Pc = 2x(20 + 5 + 1)
Pc = 2 x 26
Pc = 52cm²

b)Dane
a = 1,2 cm

V = a³
V = 1,2³
V = 1,728cm³

Pc = 6a²
Pc = 6 x 1,2²
Pc = 6 x 1,44
Pc = 8,64cm³


4.
a₁ = 0,4m = 4dm
b₁ = 15cm = 1,5dm
c₁ = 1,2dm

V₁= abc
V₁=4 x 1,5 x 1,2
V₁=6 x 1,2
V₁ = 7,2dm³

a₂ = 45cm
b₂ = 0,15m = 15cm
c₂ = 80mm = 8cm

V₂= abc
V₂=45 x 15 x 8
V₂ = 675 x 8
V₂ = 48600cm
V₂ = 4860dm³

Odp. Ten drugi.