zad 1
A. (x+1)(x-2)+(x+2)(x-1) =
B. (5k+n)(k-2n)-k(4k+n) =
C. (4y+3)(y-2)-2y(4-2y) =
D. -(3c-2)(c-1)-c(c-2) =
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a) (x+1)(x-2) + (x+2)(x-1) = (x+1)(x-1) + (x+2)(x-2) = x² - 1 + x² - 2² = x do 4 potegi -5
b)(5k+n)(k-2n)-k(4k + n)=5k² -10kn+kn-2n²-4k²-kn= k²-10kn-2n²
A =x2-2x-2+x2-x+2-2=2x2-3x-2
B= 5k2-10kn+nk-2n2-4k2-kn=k2-10kn-2n2
c= 4y2-8y+3y-6-8y+4y2=8y2-13y-6