Question

Zad 1,20-a,e,h,g zad 1,21-a,e,f

Answer 1

Zad 1.20

a) 5 * 2^5 = 5*32 = 160

e) (1/2)^3 * (2/3)^3 = 1/8 * 8/27 = 1/27

g) (2^2)^3 = 2^6 = 64

h) [(-2)^2]^3 = (-2)^6 =  64

Zad 1.21.

a) (3/7)^-2 : (9/49)^-2 = (7/3)^2 : (49/9)^2 = (7/3 * 7/3) * (9/49 * 9/49) = (3/7)^2 = 9/49

e) 1/2 *2^0 - 3^-2 = 1/2 * 1 - (1/3)^2 = 1/2 -  1/9 = 9/18 - 2/18 = 7/18

f) [2/3 + (2/3)^-2]^0 = 1

Answer 2

Zad. 1.20
a) 5•2•2•2•2•2= 160
e)=1/8•8/27 =1/27
g)=64
h)= (-2•-2)3= 4•4•4= 64