February 2019 0 73 Report
Zad. 1
Zapisz liczbę w postaci potęgi o podstawie 7.
7 x  \sqrt[5]{7} =

zad. 2
Oblicz
A. 3^{3} * 27^{-4} =
B. 2^{2} * 8^{\frac{2}{3} } =
C.  5^{3} *  125^{ -\frac{1}{3} } =
D. 81^{-0,125} =
E. 49^{ \frac{1}{2} } : 49^{ \frac{1}{4} } =
F.  \sqrt{7} ^{5} * 7^{ -\frac{3}{2} } =
G. 9^{ -\frac{3}{4} } * 27^{ -\frac{3}{2} } =
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