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h= 3cm
b=8,5a,b-podstawy trapezu
a=b-5
P=½×(a+b)×h
18 cm²=½× [a+(a-5)]×3 cm
(6b-15):2=18
6b-15=36
6b=51
b=8,5
a=8,5-5=3,5
a=b-5
h=3cm
P=[(a+b)*h]:2
P=[(b-5+b)*3]:2=18cm²
(6b-15):2=18
6b-15=36
6b=51
b=8,5
a=8,5-5=3,5
b=8,5
sprawdzenie: [(8,5+3,5)*3]:2=(12*3):2=18 zgadza sie