zad 1 .
rozwiąż równanie :
a) 2(x+3)-3(x+1)=x-13
b)1+2[3(x-1)-5(2x-3)]=2x-7
c)5(x-1)-2(x+3)]=2x-7
d)3(2x-3)+2(x-4)=4(x-2)-3(5-x)
e)4(x-2)-5(3x-9)=0
f)2(3-x)+5=3-2(x-4)
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a)
2(x+3)-3(x+1)=x-13
2x+6 -3x-3 = x-13
-x+3 = x - 13
x-x = -13-3
-2x=-16 |:(-2)
x=8
b)
1+2[3(x-1)-5(2x-3)] = 2x-7
1+2[3x-3 -10x+15] = 2x-7
1 +6x -6 -20x+30 = 2x -7
-14x+25 = 2x-7
-14x-2x = -7-25
-16x = -32 |:(-16)
x=2
c)
5(x-1)-2(x+3)]=2x-7
5x-5 -2x-6 = 2x-7
3x-11 = 2x-7
3x-2x =-7+11
x=4
d)
3(2x-3)+2(x-4) = 4(x-2)-3(5-x)
6x-9 +2x-8 = 4x-8-15+3x
8x -17 = 7x-23
8x-7x = -23+17
x = -6
e)
4(x-2)-5(3x-9)=0
4x-8 -15x+45 =0
-11x+37=0
-11x=-37 |:(-11)
f)
2(3-x)+5=3-2(x-4)
6-2x +5 = 3 -2x +8
-2x+11 = -2x+11
-2x+2x = 11-11
0=0
Rozwiązaniem jest każda liczba ;)