zad 1 ) Rozwiąż metodą podstawiania ;
a) x+y=6
x-y=3
b) x+y=12
2x-y=3
c) 2x-y=5
3x=y-6
d) y-2x=6
y=3+x
e) 3y+5x=0
3x+2y=4
f) 7x-y+17=0
5x+6y=8
g) 2x-5y=6
3x-4y=2
h) y=3x-2
y=2x+3
i) x+y=5
2x=5-2y
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a) x+y=6
x-y=3
x=3+y
3+y+y=6
x=3+y
3+2y=6
x=3+y
2y=3/:2
x=3+y
y=1,5
y=1,5
x=3+1,5
y=1,5
x=4,5
b) x+y=12
2x-y=3
x=12-y
2(12-y)-y=3
x=12-y
24-2y-y=3
x=12-y
24-3y=3
x=12-y
-3y=-21/:(-3)
y=7
x=12-7
y=7
x=5
c) 2x-y=5
3x=y-6
2x-y=5
3x-y=-6
-y=5-2x/:(-1)
3x-y=-6
y=-5+2x
3x-(-5+2x)=-6
y=-5+2x
3x+5-2x=-6
y=-5+2x
x=-11
y=-5+2*(-11)
x=-11
x=-11
y=-5-22
x=-11
y=-27
d) y-2x=6
y=3+x
3+x-2x=6
y=3+x
y=3+x
-x=3/:(-1)
x=-3
y=3-3
x=-3
y=0
f) 7x-y+17=0
5x+6y=8
-y=-7x-17/:(-1)
5x+6y=8
y=7x+17
5x+6(7x+17)=8
y=7x+17
5x+42x+102=8
y=7x+17
47x=-94/:47
x=-2
y=7*(-2)+17
x=-2
y=-14+17
x=-2
y=3
g) 2x-5y=6
3x-4y=2
2x=6+5y
3x-4y=2
x=3+2,5y
3(3+2,5y)-4y=2
x=3+2,5y
9+7,5y-4y=2
x=3+2,5y
3,5y=-7/:3,5
y=-2
x=3+2,5(-2)
y=-2
x=3-5
y=-2
x=-2
h) y=3x-2
y=2x+3
y=3x-2
3x-2=2x+3
y=3x-2
3x-2x=3+2
x=5
y=3*5-2
x=5
y=13
i) x+y=5
2x=5-2y
x=5-y
2(5-y)=5-2y
x=5-y
10-2y=5-2y
x=5-y
-2y+2y=5-10
x=5-y
0=-5
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