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√3·(√48-√27)=√(3·48)-√(3√27)=√144-√81=12-9=3
∛ = ∛(4³·4³·4³)= 4·4·4=64
ZAD3
√3≈1,71
1,7*1,7*1,7=4,913 co znaczy, że ∛4 to na pewno mniej niż 1,71, więc:
√3 > ∛4