Question

Zad 1

delta,x1,x2
Zad 2
<-4,0>
M=
m=
Zad 3

b)

Answer 1

Zad 1
y = x² - 3x - 4
Δ = (- 3)² - 4 * 1 * (- 4) = 9 + 16 = 25
√Δ = √25 = 5
x₁ = (3 - 5)/2 = - 2/2 = - 1
x₂ = (3 + 5)/2 = 8/2 = 4
zad 2
y = x² + 6x - 1    < - 4 , 0>
Δ = 6² - 4 * 1 - (- 1) = 36 + 4 = 40
W - wierzchołek = [(- 6/2) , (- 40/4)] = [- 3 , - 10]
ponieważ a > 0 to ramiona paraboli skierowane do góry
min f(- 3) = (- 3)² + 6 * (- 3) - 1 = 9 - 18 - 1 = - 10
Max f(0) = (0)² + 6 * (0) - 1 = - 1
zad 3
- x² + x ≥ 0 / * - 1
x² - x ≤ 0
x(x - 1) ≤ 0
x ≥ 0 i x ≤ 1
x ∈ < 0 , 1>
b)
x² - 4 < 0
(x + 4)(x - 4) < 0
x ∈ (- 4 , 4)