September 2018 1 34 Report

zad 1 a) (4-x)-(2x+3)+(x-4)=-(2x-3)-(x+7)

b) (4x-5)+(x-7)-(2x-8)=(-3x+4)-(x-6)

c) -(4-2x)-(2x+4)=(3x-1)+(2x-5)-(7-3x)

zad2

a) 2(x-7)-3(x+2)=4(x+3)+2(x-9)

b) -3(x+6)-6(2x+8)=-2(4-x)+9(x-8)

c) -8(x+2)+3(x+5)=-2(2x+3)+4(2x-1)

d) 6(4-x)+5(2x-5)=4(x-1)-3(4-x)


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