załącznik.... Question from @krzysiek2002

Emu96

ZAD.1

a) $8\sqrt{7}+\sqrt{7}=9\sqrt{7}$

b) $10+5\sqrt{6}-2\sqrt{6}=10+3\sqrt{6}$

c) $2\sqrt{13}-1+\sqrt{13}=3\sqrt{13}-1$

d) $3\sqrt[3]{10}-\sqrt[3]{10}=2\sqrt[3]{10}$

e) $-\sqrt[3]{5}+\sqrt[3]{-5}=-\sqrt[3]{5}-\sqrt[3]{5}=-2\sqrt[3]{5}$

f) $3\sqrt[3]{9}-\sqrt[3]{-9}= 3\sqrt[3]{9}+\sqrt[3]{9}=4\sqrt[3]{9} $

ZAD.2.

A) $\sqrt{7^{2}}+\sqrt{6}-(\sqrt{6})^{2}=7+\sqrt{6}-6=1+\sqrt{6}[tex]
B) [tex] \sqrt[3]{12^{3}}-(\sqrt{17})^{2}-\sqrt{5}=12-17-\sqrt{5}=-5-\sqrt{5}$

C) $3\sqrt{5^{2}}+2\sqrt{5}-2\sqrt[3]{(-5)^{3}}=3*5+2\sqrt{5}-2*(-5)=10+15+2\sqrt{5}=25+2\sqrt{5}$

D) $-\sqrt[3]{5^{3}}-\sqrt[3]{7}+\sqrt[3]{7}=-5-\sqrt[3]{7}+\sqrt[3]{7}=-5$

ZAD.3.

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ZAD.4.

A) $\sqrt{7^{6}}=\sqrt{(7^{3})^{2}}=7^{3}=343$

$\sqrt{12^{8}}=\sqrt{(12^{4})^{2}}=12^{4}$

b) $\sqrt[3]{5^{12}}=\sqrt[3]{(5^{4})^{3}}=5^{4}$

$\sqrt[3]{12^{9}}=\sqrt[3]{(12^{3})^{3}}=12^{3}$

c) $(\sqrt{8})^{6}=((\sqrt{8})^{2})^{3}=8^{3}=512$

$(\sqrt{6})^{10}=((\sqrt{6})^{2})^{5}=6^{5}$

d) $(\sqrt[3]{11})^{12}=((\sqrt[3]{11})^{3})^{4}=11^{4}$

$(\sqrt[3]{-9})^{21}=((\sqrt[3]{-9})^{3})^{7}=-9^{7}$

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