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y-cena gumy
3y+4x=1.90| .(-2
2y+6x=2.10| 3
-6y-8x=-3.8
6y+18x=6.3
-6y-8x+6y+18x=-3.8+6.3
10x=2.5
x=0.25
x=0.25
2y+6x=2.1
2y=2.1-1.5
2y=0.6
y=0.3
y- lizak
3x+4y=1,90 /*(-2)
2x+6y=2,10 / *3
-6x-8y=-3,8 /+
6x+18y=6,3 /+
10y=2,5 /:10
y=0,25
3x+4*0,25=1,90
3x+1=1,90
3x=0,90 /:3
x= 0,30
Odp: Guma do żucia kosztowała 0,30 zł,a lizak kosztował 0,25 zł.
y- lizaki
3x+4y=1,90 / × 2
2x+6y=2,10 / ×(-3)
6x+8y=3,8
-6x-18y= -6,30
-10y=-2,5/÷(-10)
y= 0,25
6x+8y=3,8
6x+8×0,25= 3,8
6x +2= 3,8
6x=3,8 - 2
6x=1,8 / ÷6
x= 0,3
x=0,3
y=0,25
spr. 3x +4y=1,9
3×0,3+4×0,25= 1,9
0,9+1= 1.9