97%-96%=1%
50kg-100%x-1%
0.5 kg
50-0.5=49.5 kg.
jesli zawartosc wody =97% to:
50kg=100
xkg=97%
100x=50·97
x=4850:100
x=48,5kg wody
jesli zawartosc wody =96% to:
50kg=100%
xkg=96%
100x=50·96
x=4800:100
x=48kg wody
czyli:48,50kg -48kg=0,5kg tyle wody ogorki stracily
zatem ogorki wazyly przedtem 50kg to teraz: 50kg-0,5kg=49,50kg
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97%-96%=1%
50kg-100%
x-1%
0.5 kg
50-0.5=49.5 kg.
jesli zawartosc wody =97% to:
50kg=100
xkg=97%
100x=50·97
x=4850:100
x=48,5kg wody
jesli zawartosc wody =96% to:
50kg=100%
xkg=96%
100x=50·96
x=4800:100
x=48kg wody
czyli:48,50kg -48kg=0,5kg tyle wody ogorki stracily
zatem ogorki wazyly przedtem 50kg to teraz: 50kg-0,5kg=49,50kg