Z 300g 20%-owego roztworu chlorku sodu odparowano 50g wody. Oblicz stężenie % roztworu.
20%=ms*100%/300
ms=60g
cp=60g X 100%/250
cp=24
Odp: stężenie roztworu powstałego wynosi 24%
mr₁=300g
Cp₁=20%
ms₁=?
Cp=ms/mr * 100% /*mr
Cp*mr=ms*100% /:100%
ms=Cp*mr/100%
ms₁=20%*300g/100%
ms₁=60g
ms₂=ms₁=60g
mr₂=300g-50g=250g
Cp₂=?
Cp₂=60g/250g * 100%
Cp₂=24%
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20%=ms*100%/300
ms=60g
cp=60g X 100%/250
cp=24
Odp: stężenie roztworu powstałego wynosi 24%
mr₁=300g
Cp₁=20%
ms₁=?
Cp=ms/mr * 100% /*mr
Cp*mr=ms*100% /:100%
ms=Cp*mr/100%
ms₁=20%*300g/100%
ms₁=60g
ms₂=ms₁=60g
mr₂=300g-50g=250g
Cp₂=?
Cp₂=60g/250g * 100%
Cp₂=24%