Question

(y+3) (y-1) = 2y (y+3)
pakai cara ?

Answer 1

(y+3) (y-1) = 2y (y+3)
y^2-y+3y-3 = 2y^2+6y
y^2+2y-3 = 2y^2+6y
2y^2+6y = y^2+2y-3
2y^2-y^2+6y-2y = -3
y^2+4y = -3