substitusi x=y+2 ke dalam y=2x-5
y = 2(y+2) -5
y = 2y + 4 - 5
y - 2y = -1
-y = -1
y =1
substitusi y =1 ke x =y+2
x = 1+ 2
x = 3
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substitusi x=y+2 ke dalam y=2x-5
y = 2(y+2) -5
y = 2y + 4 - 5
y - 2y = -1
-y = -1
y =1
substitusi y =1 ke x =y+2
x = 1+ 2
x = 3
y = x - 2
x - 2 = 2x - 5
x - 2x = 2 - 5
x = 3
y = 3-2
y = 1
hp = { 3 , 1 }