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x+y+z = 18
xyz = 192
ingat barisan aritmatika 2 kali bil. tengan = jumlah bil. tepinya
2y = x + z
2y = 18 - y
3y = 18
y = 6
x+z = 18 - 6
x+z = 12
x = 12 - z
xyz = 192
xz = 32
(12-z)z = 32
12z - z² = 32
z² - 12z + 32 = 0
(z - 8) (z - 4) = 0 (pemfaktoran)
z = 8 or z = 4
jadi bilanga tersebut :
x, y, z = 4, 6, 8 dengan beda 2
atau
x, y, z = 8, 6, 4 dengan beda -2