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x kwadrat -5x<x kwadrat-3do kwadratu
x kwadrat-5x< x kwadrat -9
x kwadrat-5x- x kwadrat<-9
-5x<-9 /:(-5)
x>dziewięć piatych
tak myślę...
x²-5x<3(x²-3x+3x-9)
x²-5x<3x²-9x+9x-27
x²-5x-3x²+9x-9x<27
2x²-5x<27