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2x-2x-x-2x=4
-3x=4/:-3
x=4/-3
x²-2x-2x-x = 4
x²-5x = 4
x²-5x-4 = 0
Jest to równanie kwadratowe, skorzystamy z delty
ax²+bx+c = 0
Δ = b²-4ac
Δ = 25-4*1*(-4)
Δ = 25+16
√Δ = √41
x1 = (-b-√Δ)/2a
x1 = (5-√41)/2
x2 = (-b+√Δ)/2a
x2 = (5+√41)/2
Odp. x = 5-√41)/2, lub x = (5+√41)/2.
x(x-2)-2x-x=4
x-2-2x=4
x-2x=4=2
-x=6/*(-1)
x=-6
?????