(x+√3)(x-√3)+2x(1-x)<(x-6)(x+6)
x²-3+2x-2x²<x²-36
2x²-2x-33>0
Δ = 4 + 264
Δ = 268
√Δ = 2√67
x₁=(1-√67)/2
x₂=(1+√67)/2
x ∈ (-∞; (1-√67)/2) ∨ ((1+√67)/2; ∞)
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x²-3+2x-2x²<x²-36
2x²-2x-33>0
Δ = 4 + 264
Δ = 268
√Δ = 2√67
x₁=(1-√67)/2
x₂=(1+√67)/2
x²-3+2x-2x²<x²-36
2x²-2x-33>0
Δ = 4 + 264
Δ = 268
√Δ = 2√67
x₁=(1-√67)/2
x₂=(1+√67)/2
x ∈ (-∞; (1-√67)/2) ∨ ((1+√67)/2; ∞)