Question

2x-4/x+2 + 3x-1/x+3=1 wyznać dziedzine i obicz pierwiastki

Answer 1

D: x1=-2 ;x2=-3

2x-4(x+3)/(x+2)(x+3) + 3x-1(x+2)/(x+2)(x+3)=1

2x2-6x-4x-12+3x2+6x-x-2/x2+3x+2x+6=1

5x2-5x-14/x2+5x+6

x2+5x+6=0

x1=-6; x2=1

 

D: xeR(-2,-3,-6)/(1)