Question

Zad.1 Zapisz w postaci jednej potęgi.
2^5 * 2^7 = .....
9^8 * 3^8 = .....
15^4 : 5^4 = .....
12^7 : 2^7 = .....
3^5 * 2^5 = ....
2^9 * 5^9 = ....
125^100 * 125^200 = ....
11^7 : 11^5 = ...
12^23 : 12^ -21 = ....
7^11 * 11^11 = ...

Zad. 2 Oblicz potęgi.
1^1 = ...
2^7 = ...
3^2 =....
2^ -4 = ...
3^ -3 = ...
4^4 = ...
3^5 = ....
1^15 = ....
12^2 = ....
( -1 )^3 = ...
(-1) ^6 = ....

Zad. 3 Zapisz w postaci jednej potęgi.
( 12,4^7 )^5 = ....
( 3*2^3 )^2 = ...
( 5*8^ 2 )^6 = ....
[(1 i 1/3)^3]^4 = ....
( 3*5^2 )^3 = ...
( 12*5^2) ^7 = ...
( 2^2 * 3^2 )^ -3= ...
[(2*3)^2]^3 = ....

Zad.4 Wykonaj działania

(x^2 * x^ -5)^3 / (x^3 * x^4)^2 : (x^2)^3 = ...
[a^ -4 * (a^2)^3] : [ (a^4)^3 : a^ -6 ] = ....
[(x^2 y^2)^3 * ( x^2 * y^2)] : [(x^2 * y^2)^2 * x^2 y^2 ] = ...

Zad.5 Oblicz.

( 4^2 - 3^2 )^2 + (2^2) ^4 : (2^3)^2 - 2^2 + 8^0 = ...
4^9 : (4^2)^3 - 4^2 *4 = ....

Answer 1

2^5*2^7=2^12
9^8*3^8=(9*3)^8
15^4:5^4=(15:5)^4
12^7:2^7=(12:2)^7
3^5*2^5=(3*2)^5
2^9*5^9=(2*5)^9
125^100*125^200=125^300
11^7:11^5=11^2
12^23:12^-21=-------
7^11*11^11=(7*11)^11

1^1=1
2^7=128
3^2=9
2^-4=1/16
3^-3=1/27
4^4=256
3^5=243
1^15=1
12^2=144
(-1)^3=(-1)
(-1)^6=1

(12,4^7)^5=(12,4)^35
(3*2^3)^2=(3*2)^6
(5*6^2)^6=(5*8)^12
[(1 1/3)^3]^4=(1 1/3)^12
(3*5^2)^3=(3*5)^6
(12*5^2)^7=(12*5)^14
(2^2*3^2)^-3=(2*3^4)^-3=(2*3)^12
[(2*3)^2]^3=(2*3)^6

(4^2-3^2)^2+(2^2)^4:(2^3)^2-2^2+8^0=1^4+2^8:2^6-2^2+1=1+256:64-4+1=1+4-4+1=2
4^9:(4^2)^3-4^2*4=(4^9:4^6)-(4^2*4^1)=4^3-4^2=64-16=48