(x+2y-3)^2 ile to jwest prosze o rozwaiązanie :P
(x+2y-3)^2=(x+2y-3)*(x+2y-3)= x² + 2xy - 3x + 2xy + 4y² - 6y - 3x - 6y + 9 = x² + 4y² + 4xy - 6x - 12y + 9
2 sposób:
(a + b + c)² = a² + b² + c² + 2ab + 2ac + 2bc
(x+2y + (-3))^2 = x² + 4y² + 9 + 2 * x * 2y + 2 * x * (-3) + 2 * 2y * (-3) = x² + 4y² + 9 + 4xy - 6x - 12y
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(x+2y-3)^2=(x+2y-3)*(x+2y-3)= x² + 2xy - 3x + 2xy + 4y² - 6y - 3x - 6y + 9 = x² + 4y² + 4xy - 6x - 12y + 9
2 sposób:
(a + b + c)² = a² + b² + c² + 2ab + 2ac + 2bc
(x+2y + (-3))^2 = x² + 4y² + 9 + 2 * x * 2y + 2 * x * (-3) + 2 * 2y * (-3) = x² + 4y² + 9 + 4xy - 6x - 12y