Rozwiąż równanie (x−2)(x+2)( x2+6x+8)/(x+2)(x+4)=0.... Question from @Arkatiusz

January 2019 2 17 Report

Rozwiąż równanie
(x−2)(x+2)( x2+6x+8)/(x+2)(x+4)=0

luki130193 $\frac{(x-2)(x+2)(x^2+6x+8)}{(x+2)(x+4)} =0$

$x^2+6x+8=0$
a = 1 b = 6 c = 8
Δ = $b^2-4ac=6^2-4*1*8=36-32=4$
√Δ = √4 = 2

$x_1= \frac{-b- \sqrt{delta} }{2a} = \frac{-6-2}{2*1} =- \frac{8}{2}=-4$
$x_2= \frac{-b+\sqrt{delta} }{2a} = \frac{-6+2}{2*1} =- \frac{4}{2}=-2$

$\frac{(x-2)(x+2)(x+4)(x+2)}{(x+2)(x+4)} =0$
$(x-2)(x+2)=0$
$x-2=0$ v $x+2=0$
$x=2$ $x=-2$

1 votes Thanks 0

eciaskc94 Δ=36-32=4
√Δ=2
x1=(-6-2)/2=-4
x2=(-6+2)/2=-2

(x-2)(x+2)(x+4)(x+2)/(x+2)(x+4)=0<=>x=x=2 ∨ x=-2

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Rozwiąż równanie: 2x−1/x−1 = 3+x/x+1

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