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(x^3+8)/(x+2)=x^2-2x+4
when you put the limit of two in you will get 12
(-2)^2-2(-2)+4=12
Lim x -> -2 of (x³ + 8) / (x + 2)
= Lim x -> -2 of (x³ + 2³) / (x + 2)
= Lim x -> -2 of (x + 2)(x² - 2x + 4) / (x + 2)
= Lim x -> -2 of (x² - 2x + 4)
= (-2)² - 2(-2) + 4
= 4 + 4 + 4
= 12
Cara 2:
Gunakan turunan:
Lim x -> -2 of (x³ + 8) / (x + 2)
= Lim x -> -2 of 3x² / 1
= 3(-2)² / 1
= 12