Jika turunan pertama suatu fungsi f'(x) = 4/x^2 f(2) =5 berapakah f(x).... Question from @prastiyonoe

October 2018 2 38 Report

Jika turunan pertama suatu fungsi
f'(x) = 4/x^2
f(2) =5
berapakah f(x)

anisaputrhy 4/x^2 = (4/2)^2 =5 = 2^2= 5 = 4= 5 = 5/4 = 1,25.

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izharulhaq78 $f'(x)= \frac{4}{x^2} \\ f'(x)= 4(\frac{1}{x^2}) \\ f'(x)= 4(x^{-2}) \\ \\ f(x)= \frac{4}{-1}(x^{-2+1})+c \\ f(x)= \frac{4}{-1}(x^{-1})+c \\ f(x)=-4(x^{-1})+c \\ f(x)= \frac{-4}{x}+c \\ \\ f(2)=5 \\ \frac{-4}{x}+c=5 \\ \frac{-4}{2}+c=5 \\ -2+c=5 \\ c=5+2 \\ c=7 \\ \\ f(x)=\frac{-4}{x}+c \\ f(x)=\frac{-4}{x}+7$

Maaf kalau salah

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