Tolong di bantuh y kawan kawan.... Question from @prastiyonoe

October 2018 2 22 Report

Tolong di bantuh y kawan kawan

Kilos F '' (x) = 48x²
f ' (x) = 16x³ + c

f ' (1) = 25
16(1)³ + c = 25
16 + c = 25
c = 9

f ' (x) = 16x³ + 9

f (x) = 4x^4 + 9x + c
f (-1) = 10

4(-1)^4 + 9(-1) + c = 10
4 - 9 + c = 10
-5 + c = 10
c = 15

jadi konstantanya adalah 15

0 votes Thanks 1

izharulhaq78 $f''(x)=48x^2 \\ \\ f'(x)= \frac{48}{3}x^{2+1}+c \\ f'(x)= 16x^{3}+c \\ \\ f'(1)= 25 \\16(1)^{3}+c=25 \\ 16+c=25 \\ c=25-16 \\ c=9 \\ \\ f'(x)= 16x^{3}+9 \\ \\ f(x)= \frac{16}{4}x^{3+1}+ \frac{9}{1}x^{0+1}+c \\ f(x)= 4x^{4}+9x+c \\ f(-1)= 10 \\ 4(-1)^{4}+9(-1)+c =10 \\ 4-9+c =10 \\ -5+c=10 \\ c=10+5 \\ c=15(B)$

Maaf kalau salah

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