Question

x^2 -7x+12\leq0

Answer 1

x²-7x+12 < 0

a = 1,  b = -7,  c = 12

Δ = b²-4ac = 49-48 = 1

√Δ = 1 

x1 = (-b-√Δ)2a = (7-1)/2 = 3

x2 = (-b+Δ)/2a = (7+1)/2 = 4

 

a = 1 > 0, ramiona paraboli są skierowane w dół

x ∈ (-∞;3) u (4; +∞)