Question

(x^2-6x)^2-5(x^2-6x)=14

Answer 1

[x^2-6x]^2-5[x^2-6x]=14

x^4-12x^3+36x^2-5[x^4-12x^3+36x^2]=14

x^4-12x^3+36x^2-5x^4+60x^3-180^2=14

-4x^4+48x^3-144x^2-14=0

4x^3[-x+12]-2[72x^2-7]=0

4x^3-2=0                                    i                 -x+12=0           i        72x^2-7=0

4x^3=2                                                         -x=-12                      72x^2=7

x^3=1/2                                                         x=12                         x^2=7/72

x=pierwiastek szescienny z 1/2                                                     x=pierw z 7/72

                                                                                                      i    

                                                                                                    x=- pierw z 7/72