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f(-2) = (-2)^4 + 6(-2)^3 + 3(-2)^2 + a(-2) + b = 0
-2a + b = 20
f(3) = (3)^4 + 6(3)^3 + 3(3)^2 + a(3) + b = 0
3a + b = -270
-2a + b = 20
3a + b = -270
____________ -
-5a = 290
a = -58
-2a + b = 20
-2(58) + b = 20
-116 + b = 20
b = 136
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