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a) f(x)=3/x
zał. x≠0
D=R\{0}
f(1)=3/1=3
f(3)=3/3=1
f(-3)=-1
f(-1/2)=3/(-1/2)=-6
b) f(x)=|x|+ x
D=R
f(1)=|1|+1=2,
f(3)=|3|+ 3=6
f(-3)=|-3|+ (-3)=3-3=0
f(-1/2)=|-1/2|+ (-1/2)=1/2-1/2=0